Which of the following is the correct relationship between the time required for completion of \(99.9\%\) of a first-order reaction and its half-life?
Answer & explanation
Correct answer: option 2
The correct answer is option 2. \(t_{99.9\%} = 10 × t_{1/2}\).
For a first-order reaction,
\(t= \frac{2.303}{k}log\left(\frac{a_0}{a_0 - x}\right)\)
Let us consider the initial concentration, \(a_0 = 100\)
the reaction is \(99.9\%\) is complete, so \(x = 99.9\)
So, \(a_0 - x = 100-99.9\)
Then
\(t_{99.9\%}= \frac{2.303}{k}log\left(\frac{100}{100 - 99.9}\right)\)
or, \(t_{99.9\%} = \frac{2.303}{k} × 3\)
or, \(t_{99.9\%} = \frac{6.93}{k}\) ------(i)
Since,
\(t_{1/2} = \frac{0.693}{k}\) ---------(ii)
From equation (i) and (ii) we can write
\(t_{99.9\%} = 10 × t_{1/2}\)