Two waves of amplitudes 3 m and 2 m, respectively superimpose at a point in the same phase. The resultant amplitude would be
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → 5 m
$A_1 = 3,\quad A_2 = 2$
$\text{Same phase} \Rightarrow A = A_1 + A_2$
$A = 3 + 2 = 5 \ \text{m}$
The resultant amplitude is $5 \ \text{m}$.