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Two waves of amplitudes 3 m and 2 m, respectively superimpose at a point in the same phase. The resultant amplitude would be |
1.5 m 5 m 1 m 6 m |
5 m |
The correct answer is Option (2) → 5 m $A_1 = 3,\quad A_2 = 2$ $\text{Same phase} \Rightarrow A = A_1 + A_2$ $A = 3 + 2 = 5 \ \text{m}$ The resultant amplitude is $5 \ \text{m}$. |
