The magnitude of a magnetic force on a current carrying conductor is given by:
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → $i\,lB \sin θ$
According to Lorentz force,
$F=I(\vec L×\vec B)$
$⇒|F|=ILB\sin θ$
The magnitude of a magnetic force on a current carrying conductor is given by:
Correct answer: option 3
The correct answer is Option (3) → $i\,lB \sin θ$
According to Lorentz force,
$F=I(\vec L×\vec B)$
$⇒|F|=ILB\sin θ$