In ΔABC, points E and F are on sides AB and AC respectively such that 4 AE = 3AB and 3AF= 3AC. If BC = 20 cm, then what is the length of EF (in cm) ?
Answer & explanation
Correct answer: option 3
4 AE = 3AB
AE : AB = 3 : 4
and 4AF= 3AC
AF : AC = 3 : 4
Similarly ,
EF : BC = 3 : 4
According to question,
4R = 20
1R = 5
EF = 3R
= 3 × 5 = 15
The correct answer is option (3) : 15