The matrix $\begin{bmatrix} 1 & 0 & 0 \\ 0 & 2 & 0 \\ 0 & 0 & 4 \end{bmatrix}$ is a |
identity matrix symmetric matrix skew-symmetric matrix None of these |
symmetric matrix |
The correct answer is Option (2) → symmetric matrix ## Let $A = \begin{bmatrix} 1 & 0 & 0 \\ 0 & 2 & 0 \\ 0 & 0 & 4 \end{bmatrix}$ $∴$ $A' = \begin{bmatrix} 1 & 0 & 0 \\ 0 & 2 & 0 \\ 0 & 0 & 4 \end{bmatrix} = A$ So, the given matrix is a symmetric matrix. [since, for a square matrix $A$, if $A' = A$, then $A$ is called symmetric matrix] |