Practicing Success
If 9sinθ = 4cosθ; then value of \(\frac{cosec^2 θ + sec^2 θ}{cosec^2 θ - sec^2 θ}\) is: |
\(\frac{65}{81}\) \(\frac{97}{65}\) \(\frac{17}{16}\) \(\frac{81}{65}\) |
\(\frac{97}{65}\) |
9sinθ = 4cosθ ⇒ tanθ = \(\frac{4}{9}\) cotθ = \(\frac{9}{4}\) \(\frac{cosec^2θ + sec^2 θ}{cosec^2 θ - sec^2 θ}\) ⇒ \(\frac{sec^2 θ(cot^2 θ + 1)}{sec^2 θ (cot^2 θ - 1)}\) =\(\frac{(\frac{9}{4})^2 + 1 }{(\frac{9}{4})^2 - 1}\) =\(\frac{\frac{81}{16} + 1}{\frac{81}{16} - 1}\) =\(\frac{\frac{97}{16}}{\frac{65}{16}}\) =\(\frac{97}{65}\) |