The radius of the innermost electron orbit of a hydrogen atom is $5.3 × 10^{-11}m$. The radius of the third orbit is:

$4.77 × 10^{-10} m$ $2.11 × 10^{-10} m$ $5.02 × 10^{-10} m$ $1.01× 10^{-10} m$

$4.77 × 10^{-10} m$

The correct answer is Option (1) → $4.77 × 10^{-10} m$