What is the value of last two digits of the product 4895 ×6789?

The correct answer is option (2) : 55

To find last two digits

we find $(4895 × 6789) mod\, 100$

$4895 = 95 (mod\, 100)$

$6789 = 89(mod\, 100)$

$⇒4895×6789 = (95×89) (mod\, 100)$

$= 8455(mod\, 100)$

$= 55(mod\, 100)$

∴ Last 2 digits of $4895×6789= 55$