CUET Preparation Today
What is the value of last two digits of the product $4895 ×6789$? |
50 55 60 65 |
55 |
The correct answer is option (2) : 55 To find last two digits we find $(4895 × 6789) mod\, 100$ $4895 = 95 (mod\, 100)$ $6789 = 89(mod\, 100)$ $⇒4895×6789 = (95×89) (mod\, 100)$ $= 8455(mod\, 100)$ $= 55(mod\, 100)$ ∴ Last 2 digits of $4895×6789= 55$ |
