In a series LCR circuit if the voltage across inductor, capacitor and resistor respectively are 60 V, 30 V and 40 V, then the applied voltage is:

50 V

The correct answer is Option (4) → 50 V

$V_{total}=\sqrt{V_R^2+(V_L-V_C)^2}$

where,

Voltage Across the Indicator, $V_L=60V$

Voltage Across the Capacitor, $V_C=30V$

Voltage Across the Resistor, $V_R=40V$

$V_{total}=\sqrt{(40)^2+(60-30)^2}$

$=\sqrt{1600+900}$

$=50V$