In a series LCR circuit if the voltage across inductor, capacitor and resistor respectively are 60 V, 30 V and 40 V, then the applied voltage is:
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → 50 V
$V_{total}=\sqrt{V_R^2+(V_L-V_C)^2}$
where,
Voltage Across the Indicator, $V_L=60V$
Voltage Across the Capacitor, $V_C=30V$
Voltage Across the Resistor, $V_R=40V$
$V_{total}=\sqrt{(40)^2+(60-30)^2}$
$=\sqrt{1600+900}$
$=50V$