Practicing Success
If $2 x^2-7 x y+3 y^2=0$ then find the Ratio of x, y: |
3 : 1 1 : 2 1 and 2 both 2 : 3 |
1 and 2 both |
$2 x^2-7 x y+3 y^2=0$ 2x² - 6xy - xy + 3y² = 0 2x(x - 3y ) -y ( x - 3y ) = 0 (2x-y).(x-3y) = 0 So , both (2x-y) and (x-3y) = 0 2x-y = 0 2x = y x : y = 1 : 2 And , x-3y = 0 x = 3y x : y = 3 : 1 The correct answer is Option (3) → 1 and 2 both |