a b c d

b

$\frac{V_0}{V_m} = \frac{R_0}{R_{in}}\times \beta = \frac{5\times 10^3\times 62}{500}= 620$ $V_0 = 620\times V_{in} = 620\times 0.01 = 6.2V$ $V_0 = 6.2V$