In the following reaction the value of ‘X’ is ${ }_7 N^{14}+{ }_2 H e^4 \rightarrow X+{ }_1 H^1$
Answer & explanation
Correct answer: option 2
${ }_7 N^{14}+{ }_2 He^4 \rightarrow{ }_8 O^{17}+{ }_1 H^1$
In the following reaction the value of ‘X’ is ${ }_7 N^{14}+{ }_2 H e^4 \rightarrow X+{ }_1 H^1$
Correct answer: option 2
${ }_7 N^{14}+{ }_2 He^4 \rightarrow{ }_8 O^{17}+{ }_1 H^1$