If $x (5-\frac{2}{x})=\frac{5}{x}$, then the value of $x^2 +\frac{1}{x^2}$ is equal to :
Answer & explanation
Correct answer: option 1
If $x (5-\frac{2}{x})=\frac{5}{x}$,
then,
5x - \(\frac{5}{x}\) = 2
Squaring on both the sides,
25x2 + \(\frac{25}{x^2}\) = 4 + 2×25
= 25x2 + \(\frac{25}{x^2}\) = 54
Divide the equation by 25 on the both sides,
then the value of $x^2 +\frac{1}{x^2}$ = \(\frac{54}{25}\) = $2\frac{4}{25}$