Practicing Success
The threshold frequency for a metallic surface corresponds to an energy of 6.2 eV and the stopping potential for a radiation incident on this surface is 5 V. The incident radiation lies in |
visible region X-ray region ultra-violet region infra-red region |
ultra-violet region |
$\text{Work function of the material is }\phi = 6.2eV$ $ \text{ Stopping Potential } V_s = 5V$ $ \text{ Energy of the incident radiation is } = \phi + eV_s = 11.2eV$ $ \lambda = \frac{12400}{E} = \frac{12400A^o}{11.2} = 1107A^o$ It lies in the ultra-violet region.
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