The equation of the plane which passes through the point (3, 2, -1) and perpendicular to the line with direction ratios 2, 1, 2 is :
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → $2x+y+2z=6$
The equation of a plane passing through a given point $(x_0,y_0,z_0)$ and perpendicular to a given direction ratio is,
$a(x-x_0)+b(y-y_0)+c(z-z_0)=0$
where $(a,b,c)$ are direction ratios of the normal to the plane.
$∴2(x-3)+1(y-2)+2(z+1)=0$
$⇒2x+y+2z-6=0$
$⇒2x+y+2z=6$