Two numbers are in the ratio 9 : 16. If both numbers are increased by 40, then their ratio becomes 2 : 3, What is the difference between the two numbers?
Answer & explanation
Correct answer: option 3
I : II
Original ratio 9 : 16
New ratio 2 : 3
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+40 +40
⇒ $\frac{9R + 40}{16R+40} = \frac{2}{3}$
Using cross - multiplication method,
⇒ 32R - 27R = (40 x 3) - (40 x 2)
⇒ 5R = 40
⇒ R = 8
Difference between I and II = 7R = 7 x 8 = 56