In ΔPQR, QT ⊥ PR and S is a point on QR such that ∠PSQ = x°. If ∠TQR = 48° and ∠SPR = 34°, then the value of x° is.

78° 88° 76° 80°

76°

In ΔPOT, ∠POT = 180° - (90° + 34°) = 56° ∠POT = ∠QOS = 56° (vertical opposite angle) ∠PSQ = x° = 180° - (56° + 48°) = 76°