In ΔPQR, QT ⊥ PR and S is a point on QR such that ∠PSQ = x°. If ∠TQR = 48° and ∠SPR = 34°, then the value of x° is.
Answer & explanation
Correct answer: option 3
In ΔPOT,
∠POT = 180° - (90° + 34°) = 56°
∠POT = ∠QOS = 56° (vertical opposite angle)
∠PSQ = x° = 180° - (56° + 48°) = 76°