A dice is thrown twice, the probability of occurence of 5 at least once is
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → $\frac{11}{36}$ **
The total outcomes when a dice is thrown twice = $6\times 6=36$
Probability of not getting 5 in one throw = $\frac{5}{6}$
Probability of not getting 5 in both throws = $\frac{5}{6}\times \frac{5}{6}=\frac{25}{36}$
Probability of getting 5 at least once = $1-\frac{25}{36}=\frac{11}{36}$