A dice is thrown twice, the probability of occurence of 5 at least once is

$\frac{11}{36}$

The correct answer is Option (1) → $\frac{11}{36}$ **

The total outcomes when a dice is thrown twice = $6\times 6=36$

Probability of not getting 5 in one throw = $\frac{5}{6}$

Probability of not getting 5 in both throws = $\frac{5}{6}\times \frac{5}{6}=\frac{25}{36}$

Probability of getting 5 at least once = $1-\frac{25}{36}=\frac{11}{36}$