Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B2

Chapter

Calculus

Question:

The minimum value of the function $P(x)=K_1x+\frac{K_2}{x}, (x>0, K_1 > 0, K_2 > 0)$ is :

Options:

$\sqrt{K_1K_2}$

$3\sqrt{K_1K_2}$

$2\sqrt{K_1K_2}$

No minimum value is possible

Correct Answer:

$2\sqrt{K_1K_2}$