Practicing Success
CUET Preparation Today
CUET
-- Mathematics - Section B2
Calculus
The minimum value of the function $P(x)=K_1x+\frac{K_2}{x}, (x>0, K_1 > 0, K_2 > 0)$ is :
$\sqrt{K_1K_2}$
$3\sqrt{K_1K_2}$
$2\sqrt{K_1K_2}$
No minimum value is possible