If x = 32, y = 33 and z = 35, then evaluate the expression $x^3 + y^3 +z^3 -3xyz$.

700

a³ + b³ + c³ - 3abc = \(\frac{1}{2}\)[(a + b + c) {( a- b)² + ( b - c)² + (c - a)²}]

If x = 32

y = 33

z = 35

Then evaluate the expression $x^3 + y^3 +z^3 -3xyz$

$x^3 + y^3 +z^3 -3xyz$ = \(\frac{1}{2}\)[(32 + 33 + 35) {( 32- 33)² + ( 33 - 35)² + (35 - 32)²}]

$x^3 + y^3 +z^3 -3xyz$ = \(\frac{1}{2}\)[(100) {1+ 4 + 9}]

$x^3 + y^3 +z^3 -3xyz$ = 100 × 7 = 700