Answer & explanation
Correct answer: option 2
Debroglie wavelength $\lambda = \frac{h}{p} = \frac{h}{\sqrt {2mE}} = \frac{h}{\sqrt {2mk_BT}}$
Correct answer: option 2
Debroglie wavelength $\lambda = \frac{h}{p} = \frac{h}{\sqrt {2mE}} = \frac{h}{\sqrt {2mk_BT}}$