A capacitor of \( 25\,\mu\mathrm{F} \) is connected in series with d.c. voltage of 5 V. The value of current in the circuit will be:
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → Zero
The plates of a capacitor are separated by an insulator, so no charge can flow across the gap. When a d.c. source is connected, a brief charging current flows only until the capacitor is charged to the source voltage, \( Q = CV \).
Once charged, the capacitor's voltage balances the source, and the steady current is zero. In terms of reactance, a d.c. source has \( \omega = 0 \):
\( \displaystyle X_C = \frac{1}{\omega C} \rightarrow \infty \;\Rightarrow\; I = 0 \)
NCERT (2026-27):
AC Voltage Applied to a Capacitor – “… When a capacitor is connected to a voltage source in a dc circuit, current will flow for the short time required to charge the capacitor. As charge accumulates on the capacitor plates, the voltage across them increases, opposing the current. That is, a capacitor in a dc circuit will limit or oppose the current as it charges. When the capacitor is fully charged, the current in the circuit falls to zero.”