Target Exam

CUET

Subject

-- Mathematics - Section A

Chapter

Indefinite Integration

Question:

\(\int\sqrt{\frac{1-\cos 2x}{1+\cos 2x}}dx=\)

Options:

\(\log|\cos x|+c\)

\(-\log|\cos x|+c\)

\(-\log|\sec x|+c\)

\(\log|\cos 2x|+c\)

Correct Answer:

\(-\log|\cos x|+c\)

Explanation:

\(\int\sqrt{\frac{1-\cos 2x}{1+\cos 2x}}dx=\int\sqrt{\frac{\sin^2x}{\cos^2}}dx\)

$=\int\tan x\,dx$

$=-\log|\cos x|+c$