Two dice are thrown simultaneously. If X denotes the number of fours, then the expectation of X will be: |
$\frac{5}{9}$ $\frac{1}{3}$ $\frac{4}{7}$ $\frac{3}{8}$ |
$\frac{1}{3}$ |
The correct answer is Option (2) - $\frac{1}{3}$
$E(X)=0×\frac{25}{36}+1×\frac{10}{36}+2×\frac{1}{36}$ $=\frac{10+2}{36}=\frac{1}{3}$ |