If 6 women can complete a work in 3 days, and 9 girls can complete the same work in 2 days, then find the time taken to complete the same work by 8 women and 6 girls?

9/7 days

6 Women = 3d       .. (1)

9 Girls     = 2d       .. (2)

8 Women + 6 Girls =  ?

using formula M₁D₁n₁ = M₂D₂n₂,

where    M = no. of men 

             D = no. of days 

             n = efficiency

Putting values in formula and solving it we get,

           6 x 3 x n1 = 9 x 2 x n2

           n1 : n2

           1   :  1

 Time x Efficiency =  Total work

 putting in equation (1),

  6(1) x 3 = 18

  Therefore time taken by 8W and 6G to complete the same work is,

   = \(\frac{18}{8(1)+6(1)}\) 

   = \(\frac{18}{14}\) =  \(\frac{9}{7}\),

 Answer is \(\frac{9}{7}\) days.