Maximize $z=2x-y$
Subject to constraints
$x+y ≤4, x+3y ≤ 6, x ≥ 0, y ≥ 0$.
The corner points of the feasible region are :
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → (0, 2), (4,0), (0, 0), (3, 1)
intersection point for
$x+y=4$ ...(1)
$x+3y=6$ ...(2)
Eq. (2) - Eq. (1)
$2y=2⇒y=1$
from (1) = $x=3$
corner points → $(0, 2), (4,0), (0, 0), (3, 1)$