The ratio of earth’s orbital angular momentum (about the sun) to its mass is 4.4 × 1015 m2/s. The area enclosed by earth’s orbit is approximately
Answer & explanation
Correct answer: option 1
$\frac{L}{M_{e}}=4.4 \times 10^{15} \Rightarrow \frac{M_{e} vr}{M_{e}}=4.4 \times 10^{15}$
$\Rightarrow\left(\frac{2 \pi r}{365 \times 24 \times 60 \times 60}\right) r=4.4 \times 10^{15}$
$\Rightarrow \pi r^2 \approx 7 \times 10^{22} m^2$