If sin x = cos (x - 45°) where x is an acute angle find the value of x .
Answer & explanation
Correct answer: option 3
We know that if sin A = cos B, then A + B = 90°
ATQ,
sin x = cos (x - 30°)
⇒ x + x - 30° = 90°
⇒ 2x = 120°
⇒ x = 60°
If sin x = cos (x - 45°) where x is an acute angle find the value of x .
Correct answer: option 3
We know that if sin A = cos B, then A + B = 90°
ATQ,
sin x = cos (x - 30°)
⇒ x + x - 30° = 90°
⇒ 2x = 120°
⇒ x = 60°