Steel is used to make a hemisphere bowl that is 0.37 cm thick. The bowl/s inner radius is 6 cm. Find the bowl's outside curved surface are (take $ \pi = \frac{22}{7})$

255.0548 cm²

We know that,

Curved surface area of the hemisphere = 2πr²

Inner radius = 6 cm

Thickness = 0.37 cm

According to the formula,

= Outer radius = 6  + 0.37 = 6.37 cm

= Curved surface area = 2 × \(\frac{22}{7}\) × 6.37 × 6.37 = 255.0548 cm²