Steel is used to make a hemisphere bowl that is 0.37 cm thick. The bowl/s inner radius is 6 cm. Find the bowl's outside curved surface are (take $ \pi = \frac{22}{7})$
Answer & explanation
Correct answer: option 2
We know that,
Curved surface area of the hemisphere = 2πr2
Inner radius = 6 cm
Thickness = 0.37 cm
According to the formula,
= Outer radius = 6 + 0.37 = 6.37 cm
= Curved surface area = 2 × \(\frac{22}{7}\) × 6.37 × 6.37 = 255.0548 cm2