Practicing Success
The orthogonal trajectories of the family of curves $a^{n-1} y=x^n$ are given by ( $a$ is the arbitrary constant) |
$x^n+n^2 y=$ constant $n y^2+x^2=$ constant $n^2 x+y^n=$ constant $n^2 x-y^n=$ constant |
$n y^2+x^2=$ constant |
The equation of the given family of curves is $a^{n-1} y=x^n$ .......(i) $\Rightarrow (n-1) \log a+\log y=n \log x$ Differentiating w.r.t. $x$, we get $\frac{1}{y} \frac{d y}{d x}=\frac{n}{x}$ ......(ii) This is the differential equation of the family of curves given in (i). The differential equation of the orthogonal trajectories of (i) is obtained by replacing $\frac{d y}{d x} b y-\frac{d x}{d y}$ in (ii). Replacing $\frac{d y}{d x} b y-\frac{d x}{d y}$ in (ii), we get $\frac{1}{y} \times-\frac{d x}{d y}=\frac{n}{x} \Rightarrow x d x+n y d y=0$ On integrating, we get $\frac{x^2}{2}+n \frac{y^2}{2}=C \Rightarrow x^2+n y^2=2 C$ |