If \(\sqrt[3]{x}=2y\). Then, the value of $\frac{y^3}{x}$ is _____

$\frac{1}{2}$ $\frac{2}{3}$ $\frac{1}{8}$ 8

$\frac{1}{8}$

\(\sqrt[3]{x}=2y\) Cubing on both sides x = (2y)3 x = 8y3 \(\frac{y^3}{x}\) = \(\frac{1}{8}\)