Two equal circles of radius 8 cm intersect each other such that each passes through the centre of the other. The length of the common chord is:
Answer & explanation
Correct answer: option 3
We know that,
AD = DB
Again O1A = O2A = 8 [Radius]
∠ADO1 = 90°
O1D = O2D = 4
AD = √(64 - 16)
= √48 = 4√3
AB = 2 × 4√3 = 8√3