The value of \(\frac{sin θ - 2 sin^3 θ}{2 cos^3 θ - cos θ}\) is?
Answer & explanation
Correct answer: option 2
\(\frac{sin θ - 2 sin^3 θ}{2 cos^3 θ - cos θ}\) = \(\frac{sin θ (1 - 2sin^2 θ)}{cos θ (2cos^2 θ-1)}\)
= \(\frac{sin θ (cos2 θ)}{cos θ(cos2 θ)}\) = tan θ