Practicing Success
The derivative of $\sec (\tan \sqrt{x})$ with respect to x is : |
$\frac{\sec (\tan \sqrt{x}) \tan (\tan \sqrt{x}) \sec ^2 \sqrt{x}}{2 \sqrt{x}}$ $\sec ^2(\tan \sqrt{x})$ $\frac{\sec (\tan \sqrt{x}) \tan (\tan \sqrt{x}) \sec ^2 \sqrt{x}}{x}$ $\sec ^2\left(\tan x^{\frac{1}{3}}\right)$ |
$\frac{\sec (\tan \sqrt{x}) \tan (\tan \sqrt{x}) \sec ^2 \sqrt{x}}{2 \sqrt{x}}$ |
$y = \sec (\tan \sqrt{x})$ differentiating wrt x $\frac{d y}{d x} =\sec (\tan \sqrt{x}) \tan (\tan \sqrt{x}) \frac{d}{d x}(\tan \sqrt{x})$ $=\frac{\sec (\tan \sqrt{x}) \tan (\tan \sqrt{x}) \sec ^2 \sqrt{x} \frac{d}{d x} \sqrt{x}}{\frac{d y}{d x}}$ [Using chain rule] $\frac{d y}{d x}=\frac{\sec (\tan \sqrt{x}) \tan (\tan \sqrt{x}) \sec ^2 \sqrt{x}}{2 \sqrt{x}}$ |