Practicing Success
Practicing Success
CUET Preparation Today
If $A=\left[\begin{array}{ccc}5 & 1 & 0 \\ 6 & 2 & -1\end{array}\right], B^T=\left[\begin{array}{cc}2 & 1 \\ -2 & 0 \\ 1 & 3\end{array}\right]$, then $B A^T$ is: |
$\left[\begin{array}{ll}8 & 7 \\ 5 & 3\end{array}\right]$ $\left[\begin{array}{ll}8 & 5 \\ 7 & 3\end{array}\right]$ $\left[\begin{array}{ll}3 & 7 \\ 5 & 8\end{array}\right]$ $\left[\begin{array}{ll}3 & 5 \\ 7 & 8\end{array}\right]$ |
$\left[\begin{array}{ll}8 & 7 \\ 5 & 3\end{array}\right]$ |
The correct answer is Option (1) → $\left[\begin{array}{ll}8 & 7 \\ 5 & 3\end{array}\right]$ |
