What will happen during the electrolysis of aqueous solution of \(CuSO_4\) by using platinum electrodes?
- Copper will deposit at cathode
- Copper will deposit at anode
- Oxygen will be released at anode
- Oxygen will be released at cathode
Choose the correct answer from the options given below:
Answer & explanation
Correct answer: option 3
The correct answer is option 3. A and C
The electrolysis of an aqueous solution of \(CuSO_4\) using platinum electrodes involves the reduction and oxidation reactions at the cathode and anode, respectively.
The half-reactions involved are as follows:
At the cathode (reduction):
\( \text{Cu}^{2+} + 2e^- \rightarrow \text{Cu} \)
At the anode (oxidation):
\(4 \text{OH}^- \rightarrow \text{O}_2 + 2 \text{H}_2\text{O} + 4e^- \)
From these reactions, we can determine the products:
Copper (\(Cu\)) is deposited at the cathode.
Oxygen (\(O_2\)) is released at the anode.
Therefore, the correct answer is option 3: A and C.
So, during the electrolysis of an aqueous solution of \(CuSO_4\) with platinum electrodes, copper will deposit at the cathode, and oxygen will be released at the anode.