What will happen during the electrolysis of aqueous solution of \(CuSO_4\) by using platinum electrodes?

1. Copper will deposit at cathode
2. Copper will deposit at anode
3. Oxygen will be released at anode
4. Oxygen will be released at cathode

Choose the correct answer from the options given below:

A and C

The correct answer is option 3. A and C

The electrolysis of an aqueous solution of \(CuSO_4\) using platinum electrodes involves the reduction and oxidation reactions at the cathode and anode, respectively.

The half-reactions involved are as follows:

At the cathode (reduction):

\( \text{Cu}^{2+} + 2e^- \rightarrow \text{Cu} \)

At the anode (oxidation):

\(4 \text{OH}^- \rightarrow \text{O}_2 + 2 \text{H}_2\text{O} + 4e^- \)

From these reactions, we can determine the products:
Copper (\(Cu\)) is deposited at the cathode.
Oxygen (\(O_2\)) is released at the anode.

Therefore, the correct answer is option 3: A and C.
So, during the electrolysis of an aqueous solution of \(CuSO_4\) with platinum electrodes, copper will deposit at the cathode, and oxygen will be released at the anode.