Practicing Success
The relation R defined in the set N of natural numbers defined as R = {(x, y): y = x+ 5 and x <4} is- |
reflexive only reflexive and symmetric both Transitive only None of these. |
Transitive only |
R = {(x, y): y = x+ 5 and x <4} = {(1, 6), (2, 7), (3, 8) } It is seen that (1, 1) ∉ R. So, R is not reflexive. (1, 6) ∈ R But (6, 1) ∉ R. So, R is not symmetric. Now, since there is no pair in r such that (x, y) and (y, z) ∈ R so, we need not look for the ordered pair (x, z) in R. So R is transitive. Hence R is neither reflexive, nor symmetric but it is transitive only. |