If the length of a rectangle is decreased by 16 \(\frac{2}{3}\)% and breadth is increased by 9 \(\frac{1}{11}\)%. What's the effect on area?
Answer & explanation
Correct answer: option 2
If length = l , breadth = b
Area of the rectangle = lb
New length = \(\frac{5}{6}\)l
New breadth = \(\frac{12}{11}\)b
Area becomes = (\(\frac{5}{6}\)l) × (\(\frac{12}{11}\)b)
= \(\frac{10}{11}\)l
or area decreased by 9\(\frac{1}{11}\)%
= 9\(\frac{1}{11}\)% decrease