If the length of a rectangle is decreased by 16 \(\frac{2}{3}\)% and breadth is increased by 9 \(\frac{1}{11}\)%.  What's the effect on area?

9 \(\frac{1}{11}\)%

If length = l , breadth = b

Area of the rectangle = lb

New length = \(\frac{5}{6}\)l

New breadth = \(\frac{12}{11}\)b

Area becomes = (\(\frac{5}{6}\)l) × (\(\frac{12}{11}\)b)

                     = \(\frac{10}{11}\)l

or area decreased by 9\(\frac{1}{11}\)%

= 9\(\frac{1}{11}\)% decrease