The correct answer is (2) \([Mn_3(CO)_{12}]\).
Dodecacarbonyltrimanganese(0) is a coordination compound composed of manganese (Mn) atoms and carbon monoxide (CO) ligands. In the chemical name "dodecacarbonyltrimanganese(0)," there are several key pieces of information:
1. "Dodecacarbonyl" indicates that there are 12 carbon monoxide (CO) ligands bound to the manganese atoms.
2. "Trimanganese(0)" indicates that there are three manganese (Mn) atoms present in the complex, and the "0" in parentheses denotes the oxidation state of these manganese atoms. An oxidation state of 0 means that these manganese atoms have neither gained nor lost electrons and are in their neutral state.
Now, let's break down the molecular formula \([Mn_3(CO)_{12}]\) in detail:
\(Mn_3\): This part of the formula indicates that there are three manganese (Mn) atoms in the complex.
\((CO)_{12}\): This part of the formula indicates that there are 12 carbon monoxide (CO) ligands in the complex. These ligands, represented by CO, are coordinated to the manganese atoms.
When you put it all together, \([Mn_3(CO)_{12}]\) represents a molecule with three manganese atoms at its core, each surrounded by four carbon monoxide (CO) ligands, resulting in a total of 12 CO ligands in the complex.
The correct option is (2) \([Mn_3(CO)_{12}]\), as it accurately represents the molecular formula of dodecacarbonyltrimanganese(0). |
