If 35 men can finish a work in 6 days, then in how many days can 7 men do half of the same work?

15

Using Formula,

\(\frac{M_1\;×\;D_1\;}{W_1}\) = \(\frac{M_2\;×\;D_2\;}{W_2}\)

where, M = No. of men, D = No. of days, W = Work done

⇒ \(\frac{35\;×\;6\;}{2}\) = \(\frac{7\;×\;D_2\;}{1}\)

⇒ \( { D}_{ 2} \) = 15 days.

Therefore, 7 men can do half of the same work in 15 days.