What is the magnification when the object is placed at a distance of 2f from the pole of a convex mirror?
Answer & explanation
Correct answer: option 1
$ \text{ u = -2f , F = +f}$
$\frac{1}{v} = \frac{1}{f} - \frac{1}{u} = \frac{1}{f} - \frac{1}{-2f} = \frac{3}{2f}$
$ v = \frac{2f}{3}$
$ m = \frac{-v}{u} = \frac{1}{3}$