CUET Preparation Today
What is the magnification when the object is placed at a distance of 2f from the pole of a convex mirror? |
$\frac{1}{3}$ $\frac{2}{3}$ $1$ $\frac{3}{2}$ |
$\frac{1}{3}$ |
$ \text{ u = -2f , F = +f}$ $\frac{1}{v} = \frac{1}{f} - \frac{1}{u} = \frac{1}{f} - \frac{1}{-2f} = \frac{3}{2f}$ $ v = \frac{2f}{3}$ $ m = \frac{-v}{u} = \frac{1}{3}$ |
