The wavelength of emitted wave due to energy transition in hydrogen atom from n = 3 to n = 2 energy level will be
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → 6563 Å
Using Rydberg formula,
$\frac{1}{λ}=R_H\left(\frac{1}{{n_i}^2}-\frac{1}{{n_f}^2}\right)$
$⇒\frac{1}{λ}=1.097×10^7\left(\frac{1}{2^2}-\frac{1}{3^2}\right)$
$⇒λ=6563 Å$