Practicing Success
Practicing Success
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If x = y + z = 0, then what will be the value of $(\frac{x^2}{yz})+(\frac{y^2}{zx})+(\frac{z^2}{xy})$ ? |
$\frac{3(x^2+y^2+z^2)}{xyz}$ $x^2 + y^2 + z^2$ $\frac{x^2y^2z^2}{x}$ 3 |
3 |
If x = y + z = 0, then what will be the value of $(\frac{x^2}{yz})+(\frac{y^2}{zx})+(\frac{z^2}{xy})$ Put the value of x = 2 , y = 1 and z = 1 Put these values in required equation, $(\frac{x^2}{yz})+(\frac{y^2}{zx})+(\frac{z^2}{xy})$= $(\frac{2^2}{1})+(\frac{1^2}{2})+(\frac{1^2}{2})$ = 3 |
