If x = y + z = 0, then what will be the value of $(\frac{x^2}{yz})+(\frac{y^2}{zx})+(\frac{z^2}{xy})$ ?
Answer & explanation
Correct answer: option 4
If x = y + z = 0,
then what will be the value of $(\frac{x^2}{yz})+(\frac{y^2}{zx})+(\frac{z^2}{xy})$
Put the value of x = 2 , y = 1 and z = 1
Put these values in required equation,
$(\frac{x^2}{yz})+(\frac{y^2}{zx})+(\frac{z^2}{xy})$= $(\frac{2^2}{1})+(\frac{1^2}{2})+(\frac{1^2}{2})$ = 3