The age of father 4 years ago was 8 times the age of his son. At present the age of father is 4 times that of his son. Find the present age of son.
Answer & explanation
Correct answer: option 2
At present,
Age of father = 4R and age of son = 1R
Four years ago,
Age of father = (4R - 4) and age of son = (1R - 4)
Now, ATQ
⇒ \(\frac{4R - 4}{1R - 4}\) = \(\frac{8}{1}\)
⇒ 4R - 4 = 8R - 32
⇒ 4R = 28
⇒ 1R = 7
Present age of son = 1R = 7 years