The factors of 4x2 - 8x + 3 are:
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → (2x - 3)(2x - 1)
A quadratic \(ax^2+bx+c\) is factorised by splitting the middle term into two parts whose sum is \(b\) and whose product is \(ac\). Here \(ac=4\times3=12\) and \(b=-8\), and the pair \(-6\), \(-2\) fits (sum \(-8\), product 12).
\(4x^2-8x+3=4x^2-6x-2x+3\)
\(=2x(2x-3)-1(2x-3)\)
\(=(2x-3)(2x-1)\)
Tip: With a positive constant term and a negative middle term, both brackets must have a minus sign, so Option (4) is the only possible one at a glance.