If $P(A)=\frac{2}{5}, P(B)=\frac{3}{10}$ and $P(A∩B)=\frac{1}{5}, $ then $P(A|B).(P(B'/A')$ is equal to : |
$\frac{5}{6}$ $\frac{5}{7}$ $\frac{5}{9}$ $\frac{27}{42}$ |
$\frac{5}{9}$ |
The correct answer is Option (3) → $\frac{5}{9}$ $P(A|B).P(\overline B|\overline A)=\frac{P(A∩B)(1-P(A∪B))}{P(B)P(\overline A)}$ $[∵ P(\overline B|\overline A)=P(\overline{A∪B})=1-P(A∪B)]\\ [P(A∪B)=P(A)+P(B)-P(A∩B)]$ $=\frac{5}{9}$ |