If sec θ - cosec θ = 0 and θ is an acute angle, then what is the value of $sec^2 θ + cosec^2θ $ ?
Answer & explanation
Correct answer: option 1
sec θ - cosec θ = 0
Put θ = 45º
sec θ - cosec θ
= sec 45º - cosec 45º
= \(\sqrt { 2}\) - \(\sqrt { 2}\)
= 0
Now,
sec² θ + cosec² θ
= (\(\sqrt { 2}\))² + ( \(\sqrt { 2}\))²
= 4