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If sec θ - cosec θ = 0 and θ is an acute angle, then what is the value of $sec^2 θ + cosec^2θ $ ? |
4 1 2 0 |
4 |
sec θ - cosec θ = 0 Put θ = 45º sec θ - cosec θ = sec 45º - cosec 45º = \(\sqrt { 2}\) - \(\sqrt { 2}\) = 0 Now, sec² θ + cosec² θ = (\(\sqrt { 2}\))² + ( \(\sqrt { 2}\))² = 4 |
