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If the probability for \(A\) to fail in an examination is \(0.2\) and that of \(B\) to fail is \(0.30\), then the probability that either \(A\) or \(B\) fails is |
\(0.50\) \(0.54\) \(0.44\) \(0.45\) |
\(0.44\) |
\(P(A \cup B=P(A)+P(B)-P(A \cap B)\) $P(A \cap B) = P(A).P(B) = 0.06 $ \( \Rightarrow P(A \cup B=P(A)+P(B)-P(A \cap B) = 0.2 + 0.3 -0.06 = 0.44\) |
