Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Continuity and Differentiability

Question:

The function f (x) = |x| + |x – 1| is :

Options:

continuous at x = 0 as well as at x = 1.

continuous at x = 1 but not at x = 0.

discontinuous at x = 0 as well as at x = 1.

continuous at x = 0 but not at x = 1.

Correct Answer:

continuous at x = 0 as well as at x = 1.

Explanation:

\(\lim_{x→0}\) f(x) = 1 = f(0)

\(\lim_{x→1}\) f(x) = 1 = f(1)