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If $\frac{d}{dx}\left(2\frac{d^2y}{dx^2}\right)^3=7,$ then the sum of order and degree of the differential equation is : |
3 2 5 4 |
4 |
$\frac{d}{dx}\left(2\frac{d^2y}{dx^2}\right)^3=7$ $⇒2×3\left(\frac{d^2y}{dx^2}\right)^2\left(\frac{d^3y}{dx^3}\right)=7$ order = 3, degree = 1 $3 + 1 = 4$ |
